Dear Georgina
I am very grateful to you for attention. Unfortunately I have no financial assets for carrying out of the described experiment. As the vacuum chamber is necessary for this device to exclude influence of Magnus-force . Official physics refuse to carry out this experiment. They name my formulas incorrect. But they cannot prove the criticism neither theoretically nor practically.
But I prove my correctness with VERY SIMPLE COMPARISON: At linear movement the body has only weight - m . But at rotation the weight is multiplied on a square of his radius -mR(2). And other dimensions have no value. If the flywheel will have length of 5 kilometers, its weight is multiplied only on a square of his radius.
If it is correct, so the weight of linearly moving body should be multiplied on his length, width or volume.
So itself rotary movement is incorrect, instead of my formulas... On the contrary, my equations take into account this incorrectness.
The equations are displayed here incorrectly. You can look the CORRECT EQUATIONS in the attached file.
As this theory is confirmed with experiments.
For example Тariel Кapanadze has changed an arrangement of pulleys in my generator and has lead the successful experiment. In his variant the effect of the lever is directed against centrifugal acceleration, but the generator works.
http://www.youtube.com/watch?v=90W00Yt_PLk&feature=player_embedded
Generator of Chas Chembell has the same inefficient proportions and besides many superfluous details, but works.
http://www.youtube.com/watch?v=8QD2Whs_LxA&feature=player_embedded
And in my variants the effect of the lever promotes centrifugal acceleration, but I have no money to their construction.
As to the theory. The increase of weight is a conditional term. According to the Theory of the Relativity the Weight and Energy are equivalent. Even more - the weight is one of forms of energy. Therefore the weight increases at movement.
E=mc2 either means E=m0c2 for an object at rest, or E=mrelc2 when the object is moving.
Thus exists two kinds of the "increased" weight mrel :
longitudinal --
and cross-section --
Where -- the relativistic factor.
The increase in weight depends on a direction of the force enclosed to it.
.
If force is directed perpendicularly to movement -- . ..
And if in parallel --
In a rotating body force should be directed in parallel to his linear speed. Otherwise force will brake rotation.
In my formulas of rotation linear speed is cubed just as in the theory of a relativity the relativistic factor ascends in a cube.:))) ... And it is quite correct, because centrifugal acceleration is very real factor.
The kinetic weight is taken into account in gravitation too:
Under this formula gravitation depends not only on inert weight of rest, but also from speed and a direction of movement of this weight.
So it is possible to take into account also weight of rotation which should exist because of centrifugal acceleration.
The main theme of my article consists that, if the weight is equivalent always and everywhere then centrifugal acceleration should be equivalent to usual acceleration. But centrifugal acceleration is not taken into account in equivalent formulas.
For example the formula of Newton F=ma for a rotating body is M=Iε . Where I - the moment of inertia, and ε - only angular acceleration. During stable rotation this formula is not meaningful, as angular acceleration is equal to zero. Hence force becomes equal to zero too. But this is absurdity.... In that case the body should not rotate. But it rotates - because there is a centrifugal acceleration.
Therefore I suggest that in this formula together with angular acceleration to write down centrifugal acceleration.
Also it is necessary to take into account the centrifugal acceleration in the formula of kinetic energy of a flywheel.
As centrifugal acceleration can be considered as a special case of the relativistic spin .
ᄃ - Tensor of a full pulse of system.
ᄃ
ᄃ - total 4-speed of system
ᄃ - Tensor of Levi-Civita.
Because of dissymmetricity of Levi-Civitas tensor, the 4-vector of a spin is always perpendicular to 4-speed Precisely so the vectors of centrifugal acceleration and linear speed of a flywheel are perpendicular.
In such system of the readout , in which the total pulse of system is equal to zero (i.e. during rotary movement about the axis), spatial components of the spin coincide with a vector of the moment of a pulse, and a component of time is equal to zero.
Component of time it is equal to zero in my formula
m V3 / R..
Thus a spatial component of the spin "recovers" a "dead" pulse and erects linear speed in a cubic degree.
At linear movement, a component of time t is kept, but the spin do not exist at all.
m V2 / 2t
BEST REGARDSAttachment #1: To_Georgina.doc