Hi, Mr. Kennedy,
All acceleration can easily be eliminated by letting a single clock pass two fixed clocks, as shown:
[C]-->
[A]------------------------[B]
----------------------------[C]-->
[A]------------------------[B]
Since Clock C was already moving inertially prior to its reaching and passing Clock A, and since C does not stop at Clock B, but merely meets B in passing, there is absolutely no acceleration involved.
If clocks A and B were synchronized prior to C's arrival at A, and if C matches A when it passes A, then C will NOT match B when it passes B.
This raises the important question Why do Clocks B and C not match?
Unfortunately for those of us who wish for simplicity, there are still two possible causes involved, viz., (i) Einsteinian synchronization, and (ii) intrinsic clock slowing. (By the latter, I am referring to the similar physical situation where two people who were born at approx. the same time but whose ages now differ greatly. This is an intrinsic age difference.)
Fortunately, (i) can easily be eliminated by using triplets.
Let's use Ann, Bob, and Carl. At the start, Bob passes Ann as their ages match, then Bob goes on to meet Carl as their ages also match, but when Carl goes on to catch up with Ann, their ages do NOT match.
Bob passes Ann when they are both 5 years old:
----------------------[Bob5]-->
----------------------[Ann5]
Bob goes on to meet Carl, who happens to be the same age as Bob:
-----------------------------------------[Bob9]-->.6c
----------------------------------.6c
