I thought it was probably better to do this here than on the Physics of the observer page.
Lets say Alice and Bob agree on the co-ordinate of the starting position of Alice and her clock(A) So the position of substantial A, (P1) is the agreed equivalent (I.E. corresponds to ) of the position assigned to the image of A seen by Bob (X)
Distance traveled by substantial A= length between P1 and P2
Distance of travel seen by Bob is the length between starting position Image A, X and seen image A position at 1 minute on his clock, Y . That is distance XY
Velocity of substantial A is length P1 P2 / time taken as measured by A
Velocity of Alice according to Bob and his clock (B) is length XY/ time measured by B. Not the distance between the images as seen but the measurement corresponding to those coordinates as would be measured 'on the ground'.
When image A is seen at Y object A is at P2. The difference is the distance A moves in the time it takes the light from Y to reach B
Image velocity of A is XY/ image A clock time as seen by Bob; which is equivalent to( XY YZ)/1 minute. [YZ is an unknown distance to P2]
YZ is the distance traveled at Image velocity A in the time it takes light to travel Y to B. Having found Y Z, position of Z corresponding to P2 can be found.
This is only significant at a significant proportion of light speed as light travels extremely quickly , so distance Y B is covered extremely quickly giving very little time for A to go much distance unless A is also travelling extremely quickly.
Comments welcome.