Dear Peter,
thank you very much for your clarifications.
O.k., my picture was right, despite of the fact that the charge at the equatorial plane describes a helical path over time. I conclude out of that that both particle spheres turn around perpendicular to the spin axis (= propagation axis). I assume that the direction of this spinning movement could be anti-clockwise or clockwise, as long as both particles do their turnarounds in the same direction.
Another question: The experiment is surely made with electrons (at least i do not know about 'twin-atoms' for the Bohmian EPR experiment - sorry Georgina, i confused two different cases, when saying that the experiment can also be done with atoms).
Now the question: To compensate the electrons charge, one has to adopt a certain electrical field between the two poles of the magnet, otherwise one cannot deduce anything about spin from this experiment? Am i correct with this assumption or not?
"Stefan, Hopefully you now see the answer to your 'Bohmian set up' question as simple. Think of it as the detector electron "dominating" the measurement interaction ('momentum exchange') so there is a quanta of "energy", but it's spin direction has been modulated to the DETECTOR ELECTRON spin direction when re-emitted. That is a simple 'rotation' of the poles on the y and or z axis which CONSERVES the x axis 'spin'."
This is not entirely clear to me. Coincidentally i have replied to your post above (the lions issue with Georgina), and i remarked that in my opinion the conditions at both detectors are identical, as are the properties the particles themselves have (same spin orientations, same rotations around the propagation axis). So what is causing one particle to go one way, the other particle to go the opposite way?
Last but not least: I assume that in the magnetic field of the detectors, the particles (after the modulation you mentioned) are no more the same, but two new particles are generated and send further with the same velocity the original particles may have had. Is this correct or not?
Dear Peter, thanks for your reply. Please reply again to my questions. Until now, it was a lot to get my head round it in one go, but hopefully i can grasp the full picture upcoming.
Best wishes,
Stefan