Dear Peter,
thanks again for the reply.
I shortly have to summarize what i have found until now - for the sake of not being confused about some things:
Our 90° example is with spin 1/2 particles and Stern-Gerlach instruments on both sides.
Your model states, that all pairs of particles are produced at the source such, that their respective spins are always aligned with the propagation axis. The next statement of your model is, that those two spins are created always in opposite orientations ( 'green' always pointing to the left hand side and 'red' always pointing to the right hand side - or vice versa).
So your model does not assume an ensemble of twin particles spin states to be distributed with relative frequencies around the propagation axis. There are only two discrete possibilities of pole orientations - in relation to the two particles.
You wrote
"Now each electron absorbs the wave energy (is 'charged') takes charge of it, and re-emits the energy (in almost not time at all as n=1) but now with the ELECTRONS spin direction! (again as recently shown experimentally, see fig below). In the 'twin photomultiplier' set up the new emission meets BOTH but will only ever trigger one."
Let's assume the energy which is re-emitted is our 'new' particle (say, an electron). First question: can an electron of the field absorb and re-emitt another electron? Let's assume it can and the new electron has now the spin direction of the field. For a field pointing *up*, the electron has now *spin up*.
This new electron with *spin up* has it's new spin axis again lying on its propagation axis. Right? The other particle's new spin should be then measured as *spin down*, for same settings and orientations of the magnets. But why should it, regarding your model? The settings and orientations of the magnets are the same, the directions the particles fly in can also be made the same.
The only difference between both sides of the scenario can be stated as the different order of the poles (front/back, back/front, from the perspective of the detectors).
"Now each electron absorbs the wave energy (is 'charged') takes charge of it"
Is this wave energy identical with the OAM?
Peter, i cannot understand your approach as long as you don't name the respective binary outcomes (field up/down, spin up/down, left/right side of the experimental setup, spin in/out at the rotated detector; here you can 'freely' choose) of one run of such an epxeriment for the 90° case (relative angle between the magnets = 90°):
In which directions are the poles (not spins) of the the two particles orientated when they start from the source?
What is the setting and orientation of each detector?
I am not sure if anybody can follow what you describe, until you make it explicit.
Sorry for not having grasped the full picture. I think without your help nobody can do so. Otherwise this person should come to help me!
Anyways, thanks for replying and looking forward for an explicit example.
Best wishes,
Stefan