Ed, thanks to your recent clarifications I can at last pin-point my concerns re your model:
1. "Bell's hidden constraints" (your term; my [В±1]) are hiding in your model.**
2. Your E(AB) -- in my terms -- being simply twice* the E(AB|classical), is unphysical.**
3. *The factor of 2 arises from the value of your X being в€љ2; see notes hereunder.
4. Given #2, the component probabilities in your model will not be true.
5. I make no reference here to your "Energy Exchange Theorem".
6. I trust you will be equally analytical if my FQXi2015 is accepted. It addresses (and, I believe, resolves) concerns similar to those addressed in your essay: re Bell-v-Einstein it settles the physics in Einstein's favour. It also expresses a need to relate my notation and terminology to that of QM.
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Ed, from "Edwin Eugene Klingman replied on Mar. 7, 2015 @ 20:03 GMT":
"Given the dynamics of a 3-D spin vector with a 3-D velocity in a 3-D field and a 3-D gradient, one can generate some rather complex math. But physically, one sees that, in Stern-Gerlach, the deflection is caused by the force of the gradient on the magnetic moment. If the magnetic moment is aligned with the field, the force is maximum and hence the deflection is maximum. Call this deflection X and calculate that it is given by the first term in parentheses in equation (4).
If the spin is (initially) not aligned, then the force is less than maximum, and I use energy-exchange physics to calculate how much less and show it as x in equation (4). Thus to get the actual deflection you must calculate X-x. I think you'll find that this takes care of the sign you've been so worried about.
Alice's deflection then ranges from full max to full min, based on the local angle Оё between her spin and her field, (a,О»)."
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Ed, with thanks for the above, I trust the following will help you understand my concerns.
In seeking to understand your deflection calculations, I introduced X and you have now (as above) introduced the term X-x = "actual deflection" -- which is what I sought to understand. So let my X now be "the first term in parentheses in equation (4)". X is therefore non-negative in your formulation.
Let Alice's 'actual deflection' be О"x; Bob's О"x'. Then we have:
О"x = X-x = X - X(1-cos(a,О») = Xcos(a,О»). (1)
О"x' = X-x' = X - X(1-cos(b,О»')) = X(cos(b,О»')) = -Xcos(b,О»). (2)
Thus, in preparing to compare the QM result with your own:
E(AB|QM) = -a.b; (3)
which yields, for b = a:
E(AB|QM, b = a) = -1; (4)
for comparison with your model, using (1)-(2):
E(О"x.О"x'|EEK) = E((Xcos(a,О»)).(-Xcos(b,О»))) = -X2.E((cos(a,О»).(cos(b,О»))); (5)
which yields, for b = a:
E(О"x.О"x'|EEK, b = a) = -X2.E(cos(a,О»)).(cos(a,О»)) (6)
= -X2N-1 ОЈ(cos2(a,О»j): ОЈ = ОЈjN; j = 1, 2, ..., N; N large: (7)
= -X2/2; since О»j is a random variable and so N-1 ОЈ(cos2(a,О»j) = 1/2. (8)
= -1: IFF X2 = 2 and your model is to match QM, per (4); (9)
X (= в€љ2) being the first term in parentheses in your key equation (4).
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PS: Ed, the model you use is the same as the appealing one in equations (3)-(6)** at http://viXra.org/abs/1406.0184 - version 1 version 1. But there I explained the physical significance of those (shortcut stepping-stone) equations and added the QM equations at (8)-(13). I took the short-cuts out of a later version that I also sent to you and others (11 July 2014); the shortcuts had served their purpose.
NB: **Each "Bellian constraint" [В±1] that you reject is implicit in these equations (3)-(6) -- and therefore in your model -- because:
в€љ2cos2s(a,О») is shorthand for в€љ2[+1]cos2s(a,О»)+в€љ2[-1]cos2s(a,О»'), etc., (10)
-- which is simply в€љ2 times the related classical probabilities but unphysical and therefore insufficient to deliver all the QM probabilities --
with s= 1/2 in the model you presented: replace X by в€љ2 in all the above equations and in your essay to see the underlying (but unphysical) model.
The above explaining my long-standing concerns, and happy that we share similar concerns re Bell, etc., with best regards; Gordon Watson
E & OE.