Peter,
thanks for the reply.
"Not quite. The TWO momenta (curl+AM) amplitudes are very much dependent on the FIELD ('electrons') angle relative to the particles not vice versa (which could be implied by your description). The particles relative +/- & up/down 'states' are conserved."
I have difficulties to understand this. I thought that, lets say the particle propagating to the left from the source has, say, its north pole left (at the propagation axis, since the poles are initially always at the propagation axis). The up/down 'states' are initially all on the equator, since the particle spins around itself on the equatorial line (the equator is initially oriented vertically).
The first interaction is due to a polariser with a certain angle. According to your description i concluded that the polarizer's field absorbes the particle and re-emitts a new one with the same orientation as the polarizer's field orientation. Mmhh, is this correct so far?
If yes, i further concluded that the new particle (with the new orientations) hits a photoamplifier's electron and due to its orientation, it transmits a certain momentum to the electron. But now i have to consider that these amplifiers have two channels and both channels are stimulated by the impact of the particle. The one channel is stimulated by 'curl', the other by 'momentum'. Is this the right visualization?
What i do not understand is that you wrote the "particles relative +/- & up/down 'states' are conserved". If two particles propagate from the source, the one has north pole left, the other has also north pole left. Since both particles are measured at opposite sides, their relative 'charge states' are always opposite, *if* no re-emission takes place before a measurement. The same should be true for the up/down state, right? O.k., but there are the experimenters who can indepdently change the polarizer angles from 0 up to 90°. So it can't be that 'relative' in your sentence means relative between the two particles. I guess it means the curl/momentum pair for every particle is conserved and is always +/- 1 for one particle (for one particle +1, for the other particle -1). I conclude from this that the particle's properties and architecture is completely conserved, only the space-like orientation of its properties is changed due to re-emission? Is this the correct way to think of it?
"Para5 is also wrong; For each property the max values +1 and -1 are at the opposing poles (for curl) and opposite 'sides' of the equator (up/down). So each is then 0 at 90o. We can only EVER interact with one 'side' at a time so can only 'find' one (curl/AM value pair) at a time. We don't 'add up' Bob & Alice's values. If we did we'd get 0 as one is + and one - !"
O.k., max. value + at one pole, min. value (zero charge) at the equator, max value - at the other pole. The same for the equatorial plane: max. value 'up' say at the front, min. value at the top/down and max. value 'down' at the back of the particle. Since both properties are continua, at every point of the sphere the curl/AM combinations are different from each other.
"The complimentarity of QM is the inverse relationship of curl/AM values with the angle. Add each of THOSE together and yes, you get 1."
I conclude from this that you attach to the terminus technicus of ‚up/down' also a kind of ‚charge' with + and - signs. Is this correct? If 'charge' is +1 (-1), then the other value is 0, if 'charge' is 0, the other value is +1 (-1).
"The answer is then; at 90o."
This should be the relative difference in angles between the two poarizers, is this correct?
"The answer is then; at 90o. But actually AT 90o there's around a 50:50 chance of either clicking (if set/tuned correctly)."
What prevents the two channels to both click simultaneously?
PS: 90o should be read 90 degree angle.
Best wishes,
Stefan Weckbach