Dear Paul N Butler,
Thank you very much for studying my new paper and giving some fast comments. You are confusing a bit. They are no problems at all...
............... Your words..........
......................... I looked at your paper and the biggest problems that I see are ones that I have already mentioned to you earlier in the comments.
1. The first problem is that experimental observations show that when a photon is emitted from a source that is located in a gravitational field and received by a receiver that is located at a place closer to the center of the field where the field is stronger, the receiver will register the photon as being blue shifted (its frequency will appear to be increased), which goes along ok with your theory of photons' frequencies being blue shifted when approaching a large mass. The part that you are ignoring is that the opposite is also true. When a photon is emitted from a source that is located in a gravitational field and received by a receiver that is located in a place farther away from the center of the field where the field is weaker, the receiver will register the photon as being red shifted (its frequency will appear to be decreased), This means that as a photon would travel toward a large mass its frequency would be increased, but as it passed the large mass and began to travel away from it, its frequency would be decreased back down to where it originally was since observations show that the amount of frequency change experienced by the photon is the same in either direction, so that it would always be decreased by the same amount during the trip away from the large mass as it had been increased by its trip toward the large mass. This would mean that the idea that a photon's frequency could be increased by passing a cascade of stars would not work because the increase that it would receive when it was approaching each star would be taken back by the gravitational field of the star as it moved away from it. When it reached the gravitational field of next star in the cascade it would, therefore, be back to its original frequency before it had approached the previous star in the cascade. There would be no net increase in its frequency no matter how big the cascade was. After it left the gravitational field of last star in the cascade it would be back to the original frequency that it had when it was originally emitted. ..............Reply...................
I will give an example. There was an old story. Some Greek philosopher argued a Greek Olympic runner who won gold can never overtake a tortoise which started a bit early and is ahead of him. He says by the time he moves half distance the tortoise will move some more distance. And by the time he covers half of the remaining distance, the tortoise will move some more ahead. And this argument continues.
Here you are talking about the Gravitational redshift, this is a much smaller effect. What Dynamic Universe Model proposes happens on the light rays that goes GRAZINGLY near some gravitational mass. The equations of Gr Redshift are available in Wikipedia... You can see clearly they are dependent on distances only. General case for a photon of frequency ОЅ 2 emitted at distance R 2 to observer distance R 1 (measured as distances from the gravitational center of mass) the equation
ОЅ 1 = ОЅ 2 SQRT ( R 1 ( R 2 в€' r s )/ R 2 ( R 1 в€' r s ) )
as long as R 1 , R 2 > rs holds.
https://en.wikipedia.org/wiki/Gravitational_redshift
For the Dynamic Universe Model case....
See in page 31 of the recent paper "Nucleosynthesis after frequency shifting in electromagnetic radiation near gravitating masses in Dynamic Universe Model with Math" Case3. When the velocity of gravitational mass is not exactly opposite or exactly in the same direction to the incoming light ray:
In this case the gravitational field will act as some brake or enhance the energy of the incoming light ray depending on (Cos П•) of the velocity of gravitational mass relative to incoming radiation, where (П•) is the angle between the light ray and velocity of gravitational mass .
The gravitating mass is moving with a velocity Ој in the opposite direction and applies brake on the photon. This is something similar to the case where the gravitational mass is fixed in position and the photon of the rest mass E / c2 is moving with velocity Ој Cos П• +c
Hence the initial velocity of photon = - Ој Cos П• -c. It's velocity is towards the gravitational mass. The photon is having a freefall. Its final velocity = - Ој -c - got [ where t is the time of flight of photon].
Initial Energy = m (Ој Cos П• +c)2 /2 = E (Ој Cos П• +c)2 /2 c2 = E (Ој2 Cos2 П• +c2+2Ој Cos П• c )/2c2
Final Energy = ВЅ (E / c2 )(- Ој Cos П• -c -got)2 = ВЅ (E / c2 )(Ој2 Cos2 П• +c2+go2t2+2Ој Cos П• got+2cgot+2Ој Cos П• c )
Change in Energy = ВЅ (E / c2 ) (go2t2+2Ој Cos П• got+2cgot ), here E = h П' that means
Change in Energy = ВЅ (h П' / c2 ) (go2t2+2Ој Cos П• got+2cgot )
Hence change in Frequency = П' = 1/ {2 (h / c2 ) (go2t2+2Ој Cos П• got+2cgot )}
If you want some numerical values for comparison sake you can do it...
It should be noted here....
a. The frequency change happens due to gravity of star mass, not due to relative direction of movement between grazing light ray and the star.
b. Star velocity is much much smaller compared to velocity of light. You can have a look at the equations
As the time is less I am making posts in different posts
See the original equations in Paper as suscript and super scripts I did not edit.... I will re post after answering all your observations
Best Regards
=snp