Fred,
" ... construct an arrow (vector) from a single point in the void and it can point in an infinite number of directions. If that is all there was in the void, how do you determine dimensionality?"
The vector field that points everywhere has to live in S^1 (S^0 is left-right symmetric). So right away we know that the odd dimension topology is infinitely orientable by the embedded even dimension topology of S^0, left-right and up-down continuously. Is that also true for even dimension topology > 0? S^2 won't allow an embedded S^1 object a continuous mirror image transformation of itself(the space isn't simply connected). The next odd dimension topology, S^3, is again infinitely orientable.
Almost all the participants here think in terms of factorizability in the division algebras of S^0, S^1, S^3, S^7. I think only in terms of continuity and arithmetic modulo 2. It gets us to the same place -- however, I think it helps explain why so many cling to probabilistic arithmetic descriptions of natural events:
Odd-even parity is conserved only on the even topology S^0 and not on even topologies > 0. There is no conservation of parity on the equator of S^3, where the only possible results are 1, - 1 and i. Left-right orientability is of odd parity only -- so if we think only in terms of linear algebra, it is impossible to get other than a result of - 1 (see attachment). That is, the linear array gotten by squaring all the terms is
- 1, - 1, 1.
That a unit parallelized S^3 will admit the normed division algebras is not for me a more significant fact than that parity is restored by left-right symmetry in a continuous function over the orientable manifold.
One can't think of these as left side and right side algebras, because the S^3 manifold is simply connected; i.e., functions continuous from 1 or - 1 (the imaginary condition is static) are not linear. Vector algebra can take one only so far in describing why nature conserves parity in all (classical) interactions and why the sum of terms is zero. (The sensitivity of weak atomic interactions to chirality that results in apparent parity violations helps verify the case, because one sign change among 3 nonzero elements results in linear independence.)
Best,
TomAttachment #1: S3__equator_viewed_from_simple_pole_at_infinity.docx