Excuse me, sir, but my great ignorance, I can tell you that commits serious mistakes resulting from their ignorance of quantum mechanics: First, "your perfect abstract unseen bosons"
Not my bosons, are bosons that exist and are observable: photons of light, for example, with which you can see, through the interaction of the cells of the retina of the eye, with these bosons that you call abstract.
Second error: existing and observable reality of bodies of matter, composed of a large number of quantum particles, it becomes a non-interlaced macrostate, which depends on a critical value, as a factor of the Planck mass.
Third mistake: what you call real is the result of the actual existence of quantum microstates, which interact. Any physicist knows this first-year university.
I see you have not answered my question, on the possible demonstration of the Riemann hypothesis, by quantum physics, and specifically in relation to the electric charge.
I'll give the last track, this way, to prove the Riemann hypothesis, by quantum mechanics.
For the rest: greetings
[math]\pm e/\sqrt{m_{0}^{2}\cdot G_{N}\cdot n}=1
[/math]
[math]{\displaystyle \sum_{n=1}^{\infty}}\pm e/\sqrt{m_{0}^{2}\cdot G_{N}\cdot n}={\displaystyle \sum_{n=1}^{\infty}}\frac{1}{n^{1/2}}
[/math]
Renormalization: The vacuum is neutral, the electric charge.
And this can only happen, if all non-trivial zeros, the Riemann zeta function; are values of (1/2+it). t = real number
Fulfilled, moreover, that:
[math]{\displaystyle \sum_{n=1}^{\infty}}\pm e/\sqrt{m_{0}^{2}\cdot G_{N}\cdot n}={\displaystyle \sum_{n=1}^{\infty}}\frac{1}{n^{(1/2+it)}}=0
[/math]
Be, all the imaginary parts of (1/2 + it), that satisfies:
[math]
\sum_{n=1}^{\infty}\frac{1}{n^{s}}=0\:;\: s=\frac{1}{2}+it[/math]
[math]\frac{m(VH)}{m_{e}}(1+{\displaystyle \sum_{q}}\sqrt{q^{2}})=O{\displaystyle [\sum_{n=1}^{\infty}\exp(-Im(s))]^{-1}}[/math]
Where, m(VH) is the value, in mass, the Higgs vacuum, and ,me, is the mass of the electron
And, electric chargues:
[math]{\displaystyle \sum_{q}}\sqrt{q^{2}}=\sqrt{(4/3)^{2}+(2/3)^{2}+(-1/3)^{2}+(1/3)^{2}+1^{2}}=\sqrt{31/9}[/math]
Regards